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3x-3x^2=5x+5
We move all terms to the left:
3x-3x^2-(5x+5)=0
We get rid of parentheses
-3x^2+3x-5x-5=0
We add all the numbers together, and all the variables
-3x^2-2x-5=0
a = -3; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·(-3)·(-5)
Δ = -56
Delta is less than zero, so there is no solution for the equation
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